How Many 3-Digit Numbers Can Be Formed Using the Digits 1 to 7 without Repetition?
When forming 3-digit numbers using the digits 1 through 7 without repeating any digit, the number of possible combinations can be calculated systematically. This article will explore the methods and provide a step-by-step breakdown of the solution.
Logical Order and Choices for Digits
Firstly, let's consider the logical order of forming these 3-digit numbers. A 3-digit number is represented as _ _ _. For each of these positions, you have specific choices of digits from the set {1, 2, 3, 4, 5, 6, 7}.
Hundreds Place
The hundreds place can be filled by any one of the 7 digits. Thus, we have 7 choices for the leftmost digit.
Tens Place
For the tens place, we have 6 choices left since one digit has already been used for the hundreds place. Hence, the number decreases by 1.
Units Place
For the units place, we have 5 choices remaining as two digits have already been used. The count decreases by another 1.
Thus, the total number of 3-digit numbers that can be formed is:
7 (choices for hundreds) × 6 (choices for tens) × 5 (choices for units) 210.
The Theoretical Approach: Permutations
Another way to approach this problem is by considering it as a permutation problem. For a 3-digit number, we have 3 positions which can be filled by 7 unique digits without repetition.
The formula for permutations is given by nPr n! / (n-r)!, where n is the total number of items, and r is the number of items to be selected. Here, n 7 (the digits 1 to 7) and r 3 (the 3 digits in the number).
P3,7 7! / (7-3)! 7! / 4! (7 × 6 × 5 × 4 × 3 × 2 × 1) / (4 × 3 × 2 × 1) 7 × 6 × 5 210.
Mathematical Series and Numbering Analysis
To provide a more detailed understanding, let's explore the series of numbers formed:
Sequence Start:
The sequence starts with 123 and continues up to 765. Each digit from 1 to 7 can be placed in the hundreds, tens, and units places, ensuring no digit is repeated.
Total Count:
By the principle of multiplication, the total count of 3-digit numbers is calculated as:
7 (choices for hundreds) × 6 (choices for tens) × 5 (choices for units) 210.
This can also be confirmed by the permutation formula P3,7 7 × 6 × 5 210.
Conclusion
In conclusion, the total number of 3-digit numbers that can be formed using the digits 1 to 7 without repetition is 210. This can be verified through systematic choices, permutations, or analysis of the sequence formation. The inherent logic and mathematical principles ensure that this result is accurate and can be applied in similar problems.