How to Prepare 1.5 mL of a Normal Solution with Caustic Potash 85.0 Pure
Introduction: When preparing a normal solution of Caustic Potash 85.0 pure, it is crucial to understand the proper calculation of the amount of the substance needed to achieve the desired concentration. This normal solution will have one equivalent or one mole of the solute (KOH) per liter of solution. The following guide outlines the steps to prepare exactly 1.5 mL (0.0015 L) of a normal solution using Caustic Potash with an 85.0 percent purity.
Understanding the Molar Mass Solution
Molar Mass (Molar Mass of KOH): The molar mass of KOH (Potassium Hydroxide) is 56.11 g/mol. This value represents the mass of one mole of KOH.
N-Value (n-factor): The n-factor of KOH is 1, as it contains 1 mole of OH per mole of KOH. Hence, the equivalents weight of KOH is 56.11 g/Eq.
Calculating the Moles of KOH Required
Necessary Moles of KOH: For a 1.5 mL normal solution, we need to calculate the moles of KOH required. Since a normal solution has a molar concentration of 1 M (Molarity of 1 M).
Calculation:
1. **Molarity of KOH**: 1 M
2. **Volume of Solution**: 1.5 mL 0.0015 L
3. **Number of Moles of KOH**: Molarity × Volume 1 M × 0.0015 L 0.0015 moles
Hence, 0.0015 moles of KOH are required to prepare 1.5 mL of a normal solution.
Calculating the Mass of Pure KOH Required
The mass of pure KOH required can be calculated using the following formula:
Mass of KOH (g) Number of moles of KOH × Molar Mass
0.0015 moles × 56.11 g/mol 0.084165 g
This is the mass of pure KOH needed to prepare 1.5 mL of a normal solution.
Adjusting for the Purity of Caustic Potash
Caustic Potash 85.0 Pure Measurement: The Caustic Potash available is 85.0 percent pure. This means that 100 grams of the sample contains 85 grams of pure KOH.
Calculation:
Mass of Caustic Potash Required Mass of Pure KOH / Purity (%)
0.084165 g / 85.0% 0.09902 g
Hence, 0.09902 grams of Caustic Potash 85.0 pure are required to prepare 1.5 mL of a normal solution.
Conclusion
By following these detailed steps, one can accurately calculate and prepare 1.5 mL of a normal solution using Caustic Potash with an 85.0 purity level. Understanding and applying these principles ensures the solution meets the required standards for scientific and industrial applications.
Refer to resources for additional information and further guidance.