Solving Systems of Logarithmic Equations: A Comprehensive Guide
Logarithmic equations can be quite tricky, but with a systematic approach, they become manageable. In this article, we will walk through the steps to solve the following system of equations:
1. Simplification and Basic Logarithmic Properties
To tackle the system of equations, we first recognize and utilize some fundamental properties of logarithms. The given system is:
2 cdot log3y2 cdot log3x log2y-1log2xLet's break these down step by step.
2. Solving the First Equation
We start with the first equation:
2 cdot log3y2 cdot log3xBy dividing both sides by 2, we get:
log3ylog332 cdot log3xUsing the property logabmm cdot logab, we can rewrite this as:
log3ylog39 cdotlog3xThis implies:
y3 cdotsqrt{x}3. Solving the Second Equation
Now, we move to the second equation:
log2y-11 cdotlog2xBy recognizing that log221, we can rewrite the equation as:
log2y-log22log2xCombining the logarithms using logab-logaclogabc, we get:
log2y2log2xThis implies:
y-12xThus, we have:
y2x 14. Substitution and Solving the Quadratic Equation
Now, we have two expressions for y:
y 3 · √{x}and
y 2x 1By setting these equal to each other, we get:
y 3 · √{x} similarly y 2x 1Setting these equal:
3 cdotsqrt{x}2x 1To eliminate the square root, we square both sides:
xserx 4x^2 - 5x 1 05. Applying the Quadratic Formula
Using the quadratic formula, we can solve the quadratic equation 4x^2 - 5x 1 0:
x frac{-b pm sqrt{b^2 - 4ac}}{2a}With a 4, b -5, and c 1, we find:
x frac{5 pm sqrt{25 - 16}}{8} frac{5 pm sqrt{9}}{8} frac{5 pm 3}{8}This gives us two possible values for x: x 1 and x 0.25
6. Finding Corresponding y Values
Next, we find the corresponding y values for these x values:
For x 1: y 3 · sqrt{1} 3 For x 0.25: y 3 · sqrt{0.25} 3 cdot frac{1}{2} frac{3}{2}Thus, the solutions to the system of equations are:
x 1, y 3 x 0.25, y 1.5Conclusion: Through the systematic application of logarithmic properties and solving quadratic equations, we have successfully solved the given system of equations. Understanding these steps can significantly enhance your problem-solving skills in advanced mathematics.