Solving Trigonometric Equations: Finding the Values of x and y in sin(x-y) cos(x/y) 1/2
In this article, we will delve into the process of solving a set of trigonometric equations, specifically sin(x-y) cos(x/y) 1/2. This type of problem requires a good understanding of trigonometric identities and algebraic manipulation. We will explore the step-by-step solution of these equations to find the values of x and y.
Simplifying the Problem
The given equations are:
[sin(x-y) cos(x/y) 1/2]
Let's break this down step by step, starting with the trigonometric identities and values that are known from standard trigonometry.
Step 1: Using Known Values
From standard trigonometric values, we know:
[cos(frac{pi}{3}) frac{1}{2}]
Thus, we can equate x/y to π/3 from the second equation:
[frac{x}{y} frac{pi}{3}]
Similarly, from the first equation, we know:
[sin(frac{pi}{6}) frac{1}{2}]
Therefore, the first equation can be written as:
[x - y frac{pi}{6}]
Step 2: Substituting and Solving
From the second equation, we can express y in terms of x:
[y frac{3x}{pi}]
Substitute this expression for y in the first equation:
[x - frac{3x}{pi} frac{pi}{6}]
Multiply through by π to clear the denominator:
[pi x - 3x frac{pi^2}{6}]
Factor out x:
[x(pi - 3) frac{pi^2}{6}]
Solve for x:
[x frac{pi^2}{6(pi - 3)} frac{pi^2}{6pi - 18}]
Thus, the value of x is:
[x frac{pi^2}{6pi - 18}]
Step 3: Finding the Value of y
Substitute the value of x back into the expression for y:
[y frac{3x}{pi} frac{3(pi^2)}{(6pi - 18)pi} frac{3pi}{6pi - 18}]
Simplify the expression:
[y frac{3pi}{6(pi - 3)} frac{pi}{2(pi - 3)} frac{pi}{2pi - 6}]
Thus, the value of y is:
[y frac{pi}{2pi - 6}]
Conclusion
The values of x and y that satisfy the given equations are:
[x frac{pi^2}{6pi - 18} text{ and } y frac{pi}{2pi - 6}]
These equations utilize fundamental trigonometric identities and algebraic manipulation to reach a solution, making them a great exercise for students and enthusiasts of mathematics.
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